Sweep an arbitrary contour along a helical path.
void gleSpiral (int ncp, gleDouble contour[][2], gleDouble cont_normal[][2], gleDouble up[3], gleDouble startRadius, /* spiral starts in x-y plane */ gleDouble drdTheta, /* change in radius per revolution */ gleDouble startZ, /* starting z value */ gleDouble dzdTheta, /* change in Z per revolution */ gleDouble startXform[2][3], /* starting contour affine xform */ gleDouble dXformdTheta[2][3], /* tangent change xform per revoln */ gleDouble startTheta, /* start angle in x-y plane */ gleDouble sweepTheta); /* degrees to spiral around */
number of contour points
2D contour
2D contour normals
up vector for contour
spiral starts in x-y plane
change in radius per revolution
starting z value
change in Z per revolution
starting contour affine transformation
tangent change xform per revolution
start angle in x-y plane
degrees to spiral around
Sweep an arbitrary contour along a helical path.
The axis of the helix lies along the modeling coordinate z-axis.
An affine transform can be applied as the contour is swept. For most ordinary usage, the affines should be given as NULL.
The "startXform[][]" is an affine matrix applied to the contour to deform the contour. Thus, "startXform" of the form
| cos sin 0 | | -sin cos 0 |
will rotate the contour (in the plane of the contour), while
| 1 0 tx | | 0 1 ty |
will translate the contour, and
| sx 0 0 | | 0 sy 0 |
scales along the two axes of the contour. In particular, note that
| 1 0 0 | | 0 1 0 |
is the identity matrix.
The "dXformdTheta[][]" is a differential affine matrix that is integrated while the contour is extruded. Note that this affine matrix lives in the tangent space, and so it should have the form of a generator. Thus, dx/dt's of the form
| 0 r 0 | | -r 0 0 |
rotate the the contour as it is extruded (r == 0 implies no rotation, r == 2*PI implies that the contour is rotated once, etc.), while
| 0 0 tx | | 0 0 ty |
translates the contour, and
| sx 0 0 | | 0 sy 0 |
scales it. In particular, note that
| 0 0 0 | | 0 0 0 |
is the identity matrix -- i.e. the derivatives are zero, and therefore the integral is a constant.
gleLathe
Linas Vepstas ([email protected])